Container U and Container V were filled completely with chicken powder. The total mass of
13 of the chicken powder in Container V and
111 of the chicken powder in Container U was 590 g. If
511 of the chicken powder in Container U was poured out, the total mass of the chicken powder in both containers became 2.31 kg. How much chicken powder was in
- Container U in grams?
- Container V in grams?
(a)
Let the mass of the chicken powder in Container V be V.
Let the mass of the chicken powder in Container U be U.
13 V +
111 U = 590 --- (1)
Fraction of the chicken powder left in Container U after
511 of it was poured out
= 1 -
511 =
611 1 kg = 1000 g
2.31 kg = 2310 g
1 V +
611 U = 2310
1 V = 2310 -
611 U --- (2)
Make V the same.
(1)
x3 33 V +
311 U = 1770
1 V +
311 U = 1770
1 V = 1770 -
311 U --- (3)
(3) = (2)
1770 -
311 U = 2310 -
611 X
611 U -
311 U = 2310 - 1770
311 U = 540
111 U = 540 ÷ 3 = 180
1111 U = 11 x 180 = 1980
1 U = 1980
Mass of Container U = 1980 g
(b)
From (1)
13 V + 180 = 590
13 V = 590 - 180 = 410
33 V = 3 x 410 = 1230
1 V = 1230
Mass of Container V = 1230 g
Answer(s): (a) 1980 g; (b) 1230 g