Container T and Container U were filled completely with bread flour. The total mass of ¹₃ of the bread flour in Container U and ¹₁₁ of the bread flour in Container T was 590 g. If ⁵₁₁ of the bread flour in Container T was poured out, the total mass of the bread flour in both containers became 2.28 kg. How much bread flour was in

1. Container T in grams?
2. Container U in grams?

(a)
Let the mass of the bread flour in Container U be U.
Let the mass of the bread flour in Container T be T.

¹₃ U + ¹₁₁ T = 590 --- (1)

Fraction of the bread flour left in Container T after ⁵₁₁ of it was poured out
= 1 - ⁵₁₁
= ⁶₁₁

1 kg = 1000 g
2.28 kg = 2280 g

1 U + ⁶₁₁ T = 2280
1 U = 2280 - ⁶₁₁ T --- (2)

Make U the same.

(1)_x3
³₃ U + ³₁₁ T = 1770
1 U + ³₁₁ T = 1770
1 U = 1770 - ³₁₁ T --- (3)

(3) = (2) 
1770 - ³₁₁ T = 2280 - ⁶₁₁ X
⁶₁₁ T - ³₁₁ T = 2280 - 1770
³₁₁ T = 510
¹₁₁ T = 510 ÷ 3 = 170

¹¹₁₁ T = 11 x 170 = 1870

1 T = 1870

Mass of Container T = 1870 g

(b)
From (1)
¹₃ U + 170 = 590
¹₃ U = 590 - 170 = 420

³₃ U = 3 x 420 = 1260

1 U = 1260

Mass of Container U = 1260 g

Answer(s): (a) 1870 g; (b) 1260 g