Container X and Container Y were filled completely with bread flour. The total mass of
17 of the bread flour in Container Y and
113 of the bread flour in Container X was 580 g. If
213 of the bread flour in Container X was poured out, the total mass of the bread flour in both containers became 4.74 kg. How much bread flour was in
- Container X in grams?
- Container Y in grams?
(a)
Let the mass of the bread flour in Container Y be Y.
Let the mass of the bread flour in Container X be X.
17 Y +
113 X = 580 --- (1)
Fraction of the bread flour left in Container X after
213 of it was poured out
= 1 -
213 =
1113 1 kg = 1000 g
4.74 kg = 4740 g
1 Y +
1113 X = 4740
1 Y = 4740 -
1113 X --- (2)
Make Y the same.
(1)
x7 77 Y +
713 X = 4060
1 Y +
713 X = 4060
1 Y = 4060 -
713 X --- (3)
(3) = (2)
4060 -
713 X = 4740 -
1113 X
1113 X -
713 X = 4740 - 4060
413 X = 680
113 X = 680 ÷ 4 = 170
1313 X = 13 x 170 = 2210
1 X = 2210
Mass of Container X = 2210 g
(b)
From (1)
17 Y + 170 = 580
17 Y = 580 - 170 = 410
77 Y = 7 x 410 = 2870
1 Y = 2870
Mass of Container Y = 2870 g
Answer(s): (a) 2210 g; (b) 2870 g