Container G and Container H were filled completely with curry powder. The total mass of
17 of the curry powder in Container H and
113 of the curry powder in Container G was 520 g. If
313 of the curry powder in Container G was poured out, the total mass of the curry powder in both containers became 4.03 kg. How much curry powder was in
- Container G in grams?
- Container H in grams?
(a)
Let the mass of the curry powder in Container H be H.
Let the mass of the curry powder in Container G be G.
17 H +
113 G = 520 --- (1)
Fraction of the curry powder left in Container G after
313 of it was poured out
= 1 -
313 =
1013 1 kg = 1000 g
4.03 kg = 4030 g
1 H +
1013 G = 4030
1 H = 4030 -
1013 G --- (2)
Make H the same.
(1)
x7 77 H +
713 G = 3640
1 H +
713 G = 3640
1 H = 3640 -
713 G --- (3)
(3) = (2)
3640 -
713 G = 4030 -
1013 X
1013 G -
713 G = 4030 - 3640
313 G = 390
113 G = 390 ÷ 3 = 130
1313 G = 13 x 130 = 1690
1 G = 1690
Mass of Container G = 1690 g
(b)
From (1)
17 H + 130 = 520
17 H = 520 - 130 = 390
77 H = 7 x 390 = 2730
1 H = 2730
Mass of Container H = 2730 g
Answer(s): (a) 1690 g; (b) 2730 g