Container T and Container U were filled completely with bread flour. The total mass of
16 of the bread flour in Container U and
111 of the bread flour in Container T was 460 g. If
211 of the bread flour in Container T was poured out, the total mass of the bread flour in both containers became 3.15 kg. How much bread flour was in
- Container T in grams?
- Container U in grams?
(a)
Let the mass of the bread flour in Container U be U.
Let the mass of the bread flour in Container T be T.
16 U +
111 T = 460 --- (1)
Fraction of the bread flour left in Container T after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
3.15 kg = 3150 g
1 U +
911 T = 3150
1 U = 3150 -
911 T --- (2)
Make U the same.
(1)
x6 66 U +
611 T = 2760
1 U +
611 T = 2760
1 U = 2760 -
611 T --- (3)
(3) = (2)
2760 -
611 T = 3150 -
911 X
911 T -
611 T = 3150 - 2760
311 T = 390
111 T = 390 ÷ 3 = 130
1111 T = 11 x 130 = 1430
1 T = 1430
Mass of Container T = 1430 g
(b)
From (1)
16 U + 130 = 460
16 U = 460 - 130 = 330
66 U = 6 x 330 = 1980
1 U = 1980
Mass of Container U = 1980 g
Answer(s): (a) 1430 g; (b) 1980 g