Container K and Container L were filled completely with flour. The total mass of ¹₇ of the flour in Container L and ¹₁₃ of the flour in Container K was 480 g. If ³₁₃ of the flour in Container K was poured out, the total mass of the flour in both containers became 3.9 kg. How much flour was in

1. Container K in grams?
2. Container L in grams?

(a)
Let the mass of the flour in Container L be L.
Let the mass of the flour in Container K be K.

¹₇ L + ¹₁₃ K = 480 --- (1)

Fraction of the flour left in Container K after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.9 kg = 3900 g

1 L + ¹⁰₁₃ K = 3900
1 L = 3900 - ¹⁰₁₃ K --- (2)

Make L the same.

(1)_x7
⁷₇ L + ⁷₁₃ K = 3360
1 L + ⁷₁₃ K = 3360
1 L = 3360 - ⁷₁₃ K --- (3)

(3) = (2) 
3360 - ⁷₁₃ K = 3900 - ¹⁰₁₃ X
¹⁰₁₃ K - ⁷₁₃ K = 3900 - 3360
³₁₃ K = 540
¹₁₃ K = 540 ÷ 3 = 180

¹³₁₃ K = 13 x 180 = 2340

1 K = 2340

Mass of Container K = 2340 g

(b)
From (1)
¹₇ L + 180 = 480
¹₇ L = 480 - 180 = 300

⁷₇ L = 7 x 300 = 2100

1 L = 2100

Mass of Container L = 2100 g

Answer(s): (a) 2340 g; (b) 2100 g