Container A and Container B were filled completely with bread flour. The total mass of
16 of the bread flour in Container B and
113 of the bread flour in Container A was 480 g. If
513 of the bread flour in Container A was poured out, the total mass of the bread flour in both containers became 3.08 kg. How much bread flour was in
- Container A in grams?
- Container B in grams?
(a)
Let the mass of the bread flour in Container B be B.
Let the mass of the bread flour in Container A be A.
16 B +
113 A = 480 --- (1)
Fraction of the bread flour left in Container A after
513 of it was poured out
= 1 -
513 =
813 1 kg = 1000 g
3.08 kg = 3080 g
1 B +
813 A = 3080
1 B = 3080 -
813 A --- (2)
Make B the same.
(1)
x6 66 B +
613 A = 2880
1 B +
613 A = 2880
1 B = 2880 -
613 A --- (3)
(3) = (2)
2880 -
613 A = 3080 -
813 X
813 A -
613 A = 3080 - 2880
213 A = 200
113 A = 200 ÷ 2 = 100
1313 A = 13 x 100 = 1300
1 A = 1300
Mass of Container A = 1300 g
(b)
From (1)
16 B + 100 = 480
16 B = 480 - 100 = 380
66 B = 6 x 380 = 2280
1 B = 2280
Mass of Container B = 2280 g
Answer(s): (a) 1300 g; (b) 2280 g