Container R and Container S were filled completely with chilli powder. The total mass of ¹₄ of the chilli powder in Container S and ¹₁₃ of the chilli powder in Container R was 550 g. If ³₁₃ of the chilli powder in Container R was poured out, the total mass of the chilli powder in both containers became 3.04 kg. How much chilli powder was in

1. Container R in grams?
2. Container S in grams?

(a)
Let the mass of the chilli powder in Container S be S.
Let the mass of the chilli powder in Container R be R.

¹₄ S + ¹₁₃ R = 550 --- (1)

Fraction of the chilli powder left in Container R after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.04 kg = 3040 g

1 S + ¹⁰₁₃ R = 3040
1 S = 3040 - ¹⁰₁₃ R --- (2)

Make S the same.

(1)_x4
⁴₄ S + ⁴₁₃ R = 2200
1 S + ⁴₁₃ R = 2200
1 S = 2200 - ⁴₁₃ R --- (3)

(3) = (2) 
2200 - ⁴₁₃ R = 3040 - ¹⁰₁₃ X
¹⁰₁₃ R - ⁴₁₃ R = 3040 - 2200
⁶₁₃ R = 840
¹₁₃ R = 840 ÷ 6 = 140

¹³₁₃ R = 13 x 140 = 1820

1 R = 1820

Mass of Container R = 1820 g

(b)
From (1)
¹₄ S + 140 = 550
¹₄ S = 550 - 140 = 410

⁴₄ S = 4 x 410 = 1640

1 S = 1640

Mass of Container S = 1640 g

Answer(s): (a) 1820 g; (b) 1640 g