Container E and Container F were filled completely with curry powder. The total mass of
14 of the curry powder in Container F and
113 of the curry powder in Container E was 530 g. If
513 of the curry powder in Container E was poured out, the total mass of the curry powder in both containers became 2.68 kg. How much curry powder was in
- Container E in grams?
- Container F in grams?
(a)
Let the mass of the curry powder in Container F be F.
Let the mass of the curry powder in Container E be E.
14 F +
113 E = 530 --- (1)
Fraction of the curry powder left in Container E after
513 of it was poured out
= 1 -
513 =
813 1 kg = 1000 g
2.68 kg = 2680 g
1 F +
813 E = 2680
1 F = 2680 -
813 E --- (2)
Make F the same.
(1)
x4 44 F +
413 E = 2120
1 F +
413 E = 2120
1 F = 2120 -
413 E --- (3)
(3) = (2)
2120 -
413 E = 2680 -
813 X
813 E -
413 E = 2680 - 2120
413 E = 560
113 E = 560 ÷ 4 = 140
1313 E = 13 x 140 = 1820
1 E = 1820
Mass of Container E = 1820 g
(b)
From (1)
14 F + 140 = 530
14 F = 530 - 140 = 390
44 F = 4 x 390 = 1560
1 F = 1560
Mass of Container F = 1560 g
Answer(s): (a) 1820 g; (b) 1560 g