Container U and Container V were filled completely with flour. The total mass of ¹₃ of the flour in Container V and ¹₁₁ of the flour in Container U was 650 g. If ²₁₁ of the flour in Container U was poured out, the total mass of the flour in both containers became 3.15 kg. How much flour was in

1. Container U in grams?
2. Container V in grams?

(a)
Let the mass of the flour in Container V be V.
Let the mass of the flour in Container U be U.

¹₃ V + ¹₁₁ U = 650 --- (1)

Fraction of the flour left in Container U after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
3.15 kg = 3150 g

1 V + ⁹₁₁ U = 3150
1 V = 3150 - ⁹₁₁ U --- (2)

Make V the same.

(1)_x3
³₃ V + ³₁₁ U = 1950
1 V + ³₁₁ U = 1950
1 V = 1950 - ³₁₁ U --- (3)

(3) = (2) 
1950 - ³₁₁ U = 3150 - ⁹₁₁ X
⁹₁₁ U - ³₁₁ U = 3150 - 1950
⁶₁₁ U = 1200
¹₁₁ U = 1200 ÷ 6 = 200

¹¹₁₁ U = 11 x 200 = 2200

1 U = 2200

Mass of Container U = 2200 g

(b)
From (1)
¹₃ V + 200 = 650
¹₃ V = 650 - 200 = 450

³₃ V = 3 x 450 = 1350

1 V = 1350

Mass of Container V = 1350 g

Answer(s): (a) 2200 g; (b) 1350 g