Container L and Container M were filled completely with curry powder. The total mass of ¹₆ of the curry powder in Container M and ¹₁₁ of the curry powder in Container L was 460 g. If ²₁₁ of the curry powder in Container L was poured out, the total mass of the curry powder in both containers became 3.12 kg. How much curry powder was in

1. Container L in grams?
2. Container M in grams?

(a)
Let the mass of the curry powder in Container M be M.
Let the mass of the curry powder in Container L be L.

¹₆ M + ¹₁₁ L = 460 --- (1)

Fraction of the curry powder left in Container L after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
3.12 kg = 3120 g

1 M + ⁹₁₁ L = 3120
1 M = 3120 - ⁹₁₁ L --- (2)

Make M the same.

(1)_x6
⁶₆ M + ⁶₁₁ L = 2760
1 M + ⁶₁₁ L = 2760
1 M = 2760 - ⁶₁₁ L --- (3)

(3) = (2) 
2760 - ⁶₁₁ L = 3120 - ⁹₁₁ X
⁹₁₁ L - ⁶₁₁ L = 3120 - 2760
³₁₁ L = 360
¹₁₁ L = 360 ÷ 3 = 120

¹¹₁₁ L = 11 x 120 = 1320

1 L = 1320

Mass of Container L = 1320 g

(b)
From (1)
¹₆ M + 120 = 460
¹₆ M = 460 - 120 = 340

⁶₆ M = 6 x 340 = 2040

1 M = 2040

Mass of Container M = 2040 g

Answer(s): (a) 1320 g; (b) 2040 g