Container F and Container G were filled completely with curry powder. The total mass of ¹₆ of the curry powder in Container G and ¹₁₁ of the curry powder in Container F was 540 g. If ³₁₁ of the curry powder in Container F was poured out, the total mass of the curry powder in both containers became 3.64 kg. How much curry powder was in

1. Container F in grams?
2. Container G in grams?

(a)
Let the mass of the curry powder in Container G be G.
Let the mass of the curry powder in Container F be F.

¹₆ G + ¹₁₁ F = 540 --- (1)

Fraction of the curry powder left in Container F after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
3.64 kg = 3640 g

1 G + ⁸₁₁ F = 3640
1 G = 3640 - ⁸₁₁ F --- (2)

Make G the same.

(1)_x6
⁶₆ G + ⁶₁₁ F = 3240
1 G + ⁶₁₁ F = 3240
1 G = 3240 - ⁶₁₁ F --- (3)

(3) = (2) 
3240 - ⁶₁₁ F = 3640 - ⁸₁₁ X
⁸₁₁ F - ⁶₁₁ F = 3640 - 3240
²₁₁ F = 400
¹₁₁ F = 400 ÷ 2 = 200

¹¹₁₁ F = 11 x 200 = 2200

1 F = 2200

Mass of Container F = 2200 g

(b)
From (1)
¹₆ G + 200 = 540
¹₆ G = 540 - 200 = 340

⁶₆ G = 6 x 340 = 2040

1 G = 2040

Mass of Container G = 2040 g

Answer(s): (a) 2200 g; (b) 2040 g