Container S and Container T were filled completely with rice flour. The total mass of ¹₇ of the rice flour in Container T and ¹₁₁ of the rice flour in Container S was 470 g. If ²₁₁ of the rice flour in Container S was poured out, the total mass of the rice flour in both containers became 3.49 kg. How much rice flour was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the rice flour in Container T be T.
Let the mass of the rice flour in Container S be S.

¹₇ T + ¹₁₁ S = 470 --- (1)

Fraction of the rice flour left in Container S after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
3.49 kg = 3490 g

1 T + ⁹₁₁ S = 3490
1 T = 3490 - ⁹₁₁ S --- (2)

Make T the same.

(1)_x7
⁷₇ T + ⁷₁₁ S = 3290
1 T + ⁷₁₁ S = 3290
1 T = 3290 - ⁷₁₁ S --- (3)

(3) = (2) 
3290 - ⁷₁₁ S = 3490 - ⁹₁₁ X
⁹₁₁ S - ⁷₁₁ S = 3490 - 3290
²₁₁ S = 200
¹₁₁ S = 200 ÷ 2 = 100

¹¹₁₁ S = 11 x 100 = 1100

1 S = 1100

Mass of Container S = 1100 g

(b)
From (1)
¹₇ T + 100 = 470
¹₇ T = 470 - 100 = 370

⁷₇ T = 7 x 370 = 2590

1 T = 2590

Mass of Container T = 2590 g

Answer(s): (a) 1100 g; (b) 2590 g