Container Q and Container R were filled completely with chicken powder. The total mass of ¹₃ of the chicken powder in Container R and ¹₁₃ of the chicken powder in Container Q was 490 g. If ⁴₁₃ of the chicken powder in Container Q was poured out, the total mass of the chicken powder in both containers became 2.49 kg. How much chicken powder was in

1. Container Q in grams?
2. Container R in grams?

(a)
Let the mass of the chicken powder in Container R be R.
Let the mass of the chicken powder in Container Q be Q.

¹₃ R + ¹₁₃ Q = 490 --- (1)

Fraction of the chicken powder left in Container Q after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
2.49 kg = 2490 g

1 R + ⁹₁₃ Q = 2490
1 R = 2490 - ⁹₁₃ Q --- (2)

Make R the same.

(1)_x3
³₃ R + ³₁₃ Q = 1470
1 R + ³₁₃ Q = 1470
1 R = 1470 - ³₁₃ Q --- (3)

(3) = (2) 
1470 - ³₁₃ Q = 2490 - ⁹₁₃ X
⁹₁₃ Q - ³₁₃ Q = 2490 - 1470
⁶₁₃ Q = 1020
¹₁₃ Q = 1020 ÷ 6 = 170

¹³₁₃ Q = 13 x 170 = 2210

1 Q = 2210

Mass of Container Q = 2210 g

(b)
From (1)
¹₃ R + 170 = 490
¹₃ R = 490 - 170 = 320

³₃ R = 3 x 320 = 960

1 R = 960

Mass of Container R = 960 g

Answer(s): (a) 2210 g; (b) 960 g