Container G and Container H were filled completely with bread flour. The total mass of
15 of the bread flour in Container H and
111 of the bread flour in Container G was 540 g. If
211 of the bread flour in Container G was poured out, the total mass of the bread flour in both containers became 3.14 kg. How much bread flour was in
- Container G in grams?
- Container H in grams?
(a)
Let the mass of the bread flour in Container H be H.
Let the mass of the bread flour in Container G be G.
15 H +
111 G = 540 --- (1)
Fraction of the bread flour left in Container G after
211 of it was poured out
= 1 -
211 =
911 1 kg = 1000 g
3.14 kg = 3140 g
1 H +
911 G = 3140
1 H = 3140 -
911 G --- (2)
Make H the same.
(1)
x5 55 H +
511 G = 2700
1 H +
511 G = 2700
1 H = 2700 -
511 G --- (3)
(3) = (2)
2700 -
511 G = 3140 -
911 X
911 G -
511 G = 3140 - 2700
411 G = 440
111 G = 440 ÷ 4 = 110
1111 G = 11 x 110 = 1210
1 G = 1210
Mass of Container G = 1210 g
(b)
From (1)
15 H + 110 = 540
15 H = 540 - 110 = 430
55 H = 5 x 430 = 2150
1 H = 2150
Mass of Container H = 2150 g
Answer(s): (a) 1210 g; (b) 2150 g