Container D and Container E were filled completely with flour. The total mass of ¹₇ of the flour in Container E and ¹₁₃ of the flour in Container D was 450 g. If ⁴₁₃ of the flour in Container D was poured out, the total mass of the flour in both containers became 3.37 kg. How much flour was in

1. Container D in grams?
2. Container E in grams?

(a)
Let the mass of the flour in Container E be E.
Let the mass of the flour in Container D be D.

¹₇ E + ¹₁₃ D = 450 --- (1)

Fraction of the flour left in Container D after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
3.37 kg = 3370 g

1 E + ⁹₁₃ D = 3370
1 E = 3370 - ⁹₁₃ D --- (2)

Make E the same.

(1)_x7
⁷₇ E + ⁷₁₃ D = 3150
1 E + ⁷₁₃ D = 3150
1 E = 3150 - ⁷₁₃ D --- (3)

(3) = (2) 
3150 - ⁷₁₃ D = 3370 - ⁹₁₃ X
⁹₁₃ D - ⁷₁₃ D = 3370 - 3150
²₁₃ D = 220
¹₁₃ D = 220 ÷ 2 = 110

¹³₁₃ D = 13 x 110 = 1430

1 D = 1430

Mass of Container D = 1430 g

(b)
From (1)
¹₇ E + 110 = 450
¹₇ E = 450 - 110 = 340

⁷₇ E = 7 x 340 = 2380

1 E = 2380

Mass of Container E = 2380 g

Answer(s): (a) 1430 g; (b) 2380 g