Container B and Container C were filled completely with flour. The total mass of ¹₃ of the flour in Container C and ¹₁₃ of the flour in Container B was 480 g. If ³₁₃ of the flour in Container B was poured out, the total mass of the flour in both containers became 2.63 kg. How much flour was in

1. Container B in grams?
2. Container C in grams?

(a)
Let the mass of the flour in Container C be C.
Let the mass of the flour in Container B be B.

¹₃ C + ¹₁₃ B = 480 --- (1)

Fraction of the flour left in Container B after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
2.63 kg = 2630 g

1 C + ¹⁰₁₃ B = 2630
1 C = 2630 - ¹⁰₁₃ B --- (2)

Make C the same.

(1)_x3
³₃ C + ³₁₃ B = 1440
1 C + ³₁₃ B = 1440
1 C = 1440 - ³₁₃ B --- (3)

(3) = (2) 
1440 - ³₁₃ B = 2630 - ¹⁰₁₃ X
¹⁰₁₃ B - ³₁₃ B = 2630 - 1440
⁷₁₃ B = 1190
¹₁₃ B = 1190 ÷ 7 = 170

¹³₁₃ B = 13 x 170 = 2210

1 B = 2210

Mass of Container B = 2210 g

(b)
From (1)
¹₃ C + 170 = 480
¹₃ C = 480 - 170 = 310

³₃ C = 3 x 310 = 930

1 C = 930

Mass of Container C = 930 g

Answer(s): (a) 2210 g; (b) 930 g