Container N and Container P were filled completely with flour. The total mass of ¹₄ of the flour in Container P and ¹₁₃ of the flour in Container N was 430 g. If ³₁₃ of the flour in Container N was poured out, the total mass of the flour in both containers became 2.38 kg. How much flour was in

1. Container N in grams?
2. Container P in grams?

(a)
Let the mass of the flour in Container P be P.
Let the mass of the flour in Container N be N.

¹₄ P + ¹₁₃ N = 430 --- (1)

Fraction of the flour left in Container N after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
2.38 kg = 2380 g

1 P + ¹⁰₁₃ N = 2380
1 P = 2380 - ¹⁰₁₃ N --- (2)

Make P the same.

(1)_x4
⁴₄ P + ⁴₁₃ N = 1720
1 P + ⁴₁₃ N = 1720
1 P = 1720 - ⁴₁₃ N --- (3)

(3) = (2) 
1720 - ⁴₁₃ N = 2380 - ¹⁰₁₃ X
¹⁰₁₃ N - ⁴₁₃ N = 2380 - 1720
⁶₁₃ N = 660
¹₁₃ N = 660 ÷ 6 = 110

¹³₁₃ N = 13 x 110 = 1430

1 N = 1430

Mass of Container N = 1430 g

(b)
From (1)
¹₄ P + 110 = 430
¹₄ P = 430 - 110 = 320

⁴₄ P = 4 x 320 = 1280

1 P = 1280

Mass of Container P = 1280 g

Answer(s): (a) 1430 g; (b) 1280 g