Container W and Container X were filled completely with rice flour. The total mass of ¹₅ of the rice flour in Container X and ¹₁₁ of the rice flour in Container W was 490 g. If ⁴₁₁ of the rice flour in Container W was poured out, the total mass of the rice flour in both containers became 2.67 kg. How much rice flour was in

1. Container W in grams?
2. Container X in grams?

(a)
Let the mass of the rice flour in Container X be X.
Let the mass of the rice flour in Container W be W.

¹₅ X + ¹₁₁ W = 490 --- (1)

Fraction of the rice flour left in Container W after ⁴₁₁ of it was poured out
= 1 - ⁴₁₁
= ⁷₁₁

1 kg = 1000 g
2.67 kg = 2670 g

1 X + ⁷₁₁ W = 2670
1 X = 2670 - ⁷₁₁ W --- (2)

Make X the same.

(1)_x5
⁵₅ X + ⁵₁₁ W = 2450
1 X + ⁵₁₁ W = 2450
1 X = 2450 - ⁵₁₁ W --- (3)

(3) = (2) 
2450 - ⁵₁₁ W = 2670 - ⁷₁₁ X
⁷₁₁ W - ⁵₁₁ W = 2670 - 2450
²₁₁ W = 220
¹₁₁ W = 220 ÷ 2 = 110

¹¹₁₁ W = 11 x 110 = 1210

1 W = 1210

Mass of Container W = 1210 g

(b)
From (1)
¹₅ X + 110 = 490
¹₅ X = 490 - 110 = 380

⁵₅ X = 5 x 380 = 1900

1 X = 1900

Mass of Container X = 1900 g

Answer(s): (a) 1210 g; (b) 1900 g