Container R and Container S were filled completely with chilli powder. The total mass of ¹₆ of the chilli powder in Container S and ¹₁₃ of the chilli powder in Container R was 490 g. If ⁴₁₃ of the chilli powder in Container R was poured out, the total mass of the chilli powder in both containers became 3.33 kg. How much chilli powder was in

1. Container R in grams?
2. Container S in grams?

(a)
Let the mass of the chilli powder in Container S be S.
Let the mass of the chilli powder in Container R be R.

¹₆ S + ¹₁₃ R = 490 --- (1)

Fraction of the chilli powder left in Container R after ⁴₁₃ of it was poured out
= 1 - ⁴₁₃
= ⁹₁₃

1 kg = 1000 g
3.33 kg = 3330 g

1 S + ⁹₁₃ R = 3330
1 S = 3330 - ⁹₁₃ R --- (2)

Make S the same.

(1)_x6
⁶₆ S + ⁶₁₃ R = 2940
1 S + ⁶₁₃ R = 2940
1 S = 2940 - ⁶₁₃ R --- (3)

(3) = (2) 
2940 - ⁶₁₃ R = 3330 - ⁹₁₃ X
⁹₁₃ R - ⁶₁₃ R = 3330 - 2940
³₁₃ R = 390
¹₁₃ R = 390 ÷ 3 = 130

¹³₁₃ R = 13 x 130 = 1690

1 R = 1690

Mass of Container R = 1690 g

(b)
From (1)
¹₆ S + 130 = 490
¹₆ S = 490 - 130 = 360

⁶₆ S = 6 x 360 = 2160

1 S = 2160

Mass of Container S = 2160 g

Answer(s): (a) 1690 g; (b) 2160 g