Container V and Container W were filled completely with flour. The total mass of ¹₃ of the flour in Container W and ¹₁₁ of the flour in Container V was 440 g. If ²₁₁ of the flour in Container V was poured out, the total mass of the flour in both containers became 1.92 kg. How much flour was in

1. Container V in grams?
2. Container W in grams?

(a)
Let the mass of the flour in Container W be W.
Let the mass of the flour in Container V be V.

¹₃ W + ¹₁₁ V = 440 --- (1)

Fraction of the flour left in Container V after ²₁₁ of it was poured out
= 1 - ²₁₁
= ⁹₁₁

1 kg = 1000 g
1.92 kg = 1920 g

1 W + ⁹₁₁ V = 1920
1 W = 1920 - ⁹₁₁ V --- (2)

Make W the same.

(1)_x3
³₃ W + ³₁₁ V = 1320
1 W + ³₁₁ V = 1320
1 W = 1320 - ³₁₁ V --- (3)

(3) = (2) 
1320 - ³₁₁ V = 1920 - ⁹₁₁ X
⁹₁₁ V - ³₁₁ V = 1920 - 1320
⁶₁₁ V = 600
¹₁₁ V = 600 ÷ 6 = 100

¹¹₁₁ V = 11 x 100 = 1100

1 V = 1100

Mass of Container V = 1100 g

(b)
From (1)
¹₃ W + 100 = 440
¹₃ W = 440 - 100 = 340

³₃ W = 3 x 340 = 1020

1 W = 1020

Mass of Container W = 1020 g

Answer(s): (a) 1100 g; (b) 1020 g