Container J and Container K were filled completely with rice flour. The total mass of ¹₇ of the rice flour in Container K and ¹₁₃ of the rice flour in Container J was 630 g. If ²₁₃ of the rice flour in Container J was poured out, the total mass of the rice flour in both containers became 5.21 kg. How much rice flour was in

1. Container J in grams?
2. Container K in grams?

(a)
Let the mass of the rice flour in Container K be K.
Let the mass of the rice flour in Container J be J.

¹₇ K + ¹₁₃ J = 630 --- (1)

Fraction of the rice flour left in Container J after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
5.21 kg = 5210 g

1 K + ¹¹₁₃ J = 5210
1 K = 5210 - ¹¹₁₃ J --- (2)

Make K the same.

(1)_x7
⁷₇ K + ⁷₁₃ J = 4410
1 K + ⁷₁₃ J = 4410
1 K = 4410 - ⁷₁₃ J --- (3)

(3) = (2) 
4410 - ⁷₁₃ J = 5210 - ¹¹₁₃ X
¹¹₁₃ J - ⁷₁₃ J = 5210 - 4410
⁴₁₃ J = 800
¹₁₃ J = 800 ÷ 4 = 200

¹³₁₃ J = 13 x 200 = 2600

1 J = 2600

Mass of Container J = 2600 g

(b)
From (1)
¹₇ K + 200 = 630
¹₇ K = 630 - 200 = 430

⁷₇ K = 7 x 430 = 3010

1 K = 3010

Mass of Container K = 3010 g

Answer(s): (a) 2600 g; (b) 3010 g