Container Y and Container Z were filled completely with chilli powder. The total mass of ¹₃ of the chilli powder in Container Z and ¹₁₃ of the chilli powder in Container Y was 500 g. If ³₁₃ of the chilli powder in Container Y was poured out, the total mass of the chilli powder in both containers became 2.48 kg. How much chilli powder was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the chilli powder in Container Z be Z.
Let the mass of the chilli powder in Container Y be Y.

¹₃ Z + ¹₁₃ Y = 500 --- (1)

Fraction of the chilli powder left in Container Y after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
2.48 kg = 2480 g

1 Z + ¹⁰₁₃ Y = 2480
1 Z = 2480 - ¹⁰₁₃ Y --- (2)

Make Z the same.

(1)_x3
³₃ Z + ³₁₃ Y = 1500
1 Z + ³₁₃ Y = 1500
1 Z = 1500 - ³₁₃ Y --- (3)

(3) = (2) 
1500 - ³₁₃ Y = 2480 - ¹⁰₁₃ X
¹⁰₁₃ Y - ³₁₃ Y = 2480 - 1500
⁷₁₃ Y = 980
¹₁₃ Y = 980 ÷ 7 = 140

¹³₁₃ Y = 13 x 140 = 1820

1 Y = 1820

Mass of Container Y = 1820 g

(b)
From (1)
¹₃ Z + 140 = 500
¹₃ Z = 500 - 140 = 360

³₃ Z = 3 x 360 = 1080

1 Z = 1080

Mass of Container Z = 1080 g

Answer(s): (a) 1820 g; (b) 1080 g