Container Y and Container Z were filled completely with chicken powder. The total mass of ¹₈ of the chicken powder in Container Z and ¹₁₃ of the chicken powder in Container Y was 550 g. If ³₁₃ of the chicken powder in Container Y was poured out, the total mass of the chicken powder in both containers became 4.66 kg. How much chicken powder was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the chicken powder in Container Z be Z.
Let the mass of the chicken powder in Container Y be Y.

¹₈ Z + ¹₁₃ Y = 550 --- (1)

Fraction of the chicken powder left in Container Y after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
4.66 kg = 4660 g

1 Z + ¹⁰₁₃ Y = 4660
1 Z = 4660 - ¹⁰₁₃ Y --- (2)

Make Z the same.

(1)_x8
⁸₈ Z + ⁸₁₃ Y = 4400
1 Z + ⁸₁₃ Y = 4400
1 Z = 4400 - ⁸₁₃ Y --- (3)

(3) = (2) 
4400 - ⁸₁₃ Y = 4660 - ¹⁰₁₃ X
¹⁰₁₃ Y - ⁸₁₃ Y = 4660 - 4400
²₁₃ Y = 260
¹₁₃ Y = 260 ÷ 2 = 130

¹³₁₃ Y = 13 x 130 = 1690

1 Y = 1690

Mass of Container Y = 1690 g

(b)
From (1)
¹₈ Z + 130 = 550
¹₈ Z = 550 - 130 = 420

⁸₈ Z = 8 x 420 = 3360

1 Z = 3360

Mass of Container Z = 3360 g

Answer(s): (a) 1690 g; (b) 3360 g