Container H and Container J were filled completely with bread flour. The total mass of ¹₄ of the bread flour in Container J and ¹₁₁ of the bread flour in Container H was 530 g. If ⁵₁₁ of the bread flour in Container H was poured out, the total mass of the bread flour in both containers became 2.5 kg. How much bread flour was in

1. Container H in grams?
2. Container J in grams?

(a)
Let the mass of the bread flour in Container J be J.
Let the mass of the bread flour in Container H be H.

¹₄ J + ¹₁₁ H = 530 --- (1)

Fraction of the bread flour left in Container H after ⁵₁₁ of it was poured out
= 1 - ⁵₁₁
= ⁶₁₁

1 kg = 1000 g
2.5 kg = 2500 g

1 J + ⁶₁₁ H = 2500
1 J = 2500 - ⁶₁₁ H --- (2)

Make J the same.

(1)_x4
⁴₄ J + ⁴₁₁ H = 2120
1 J + ⁴₁₁ H = 2120
1 J = 2120 - ⁴₁₁ H --- (3)

(3) = (2) 
2120 - ⁴₁₁ H = 2500 - ⁶₁₁ X
⁶₁₁ H - ⁴₁₁ H = 2500 - 2120
²₁₁ H = 380
¹₁₁ H = 380 ÷ 2 = 190

¹¹₁₁ H = 11 x 190 = 2090

1 H = 2090

Mass of Container H = 2090 g

(b)
From (1)
¹₄ J + 190 = 530
¹₄ J = 530 - 190 = 340

⁴₄ J = 4 x 340 = 1360

1 J = 1360

Mass of Container J = 1360 g

Answer(s): (a) 2090 g; (b) 1360 g