Container M and Container N were filled completely with chilli powder. The total mass of ¹₄ of the chilli powder in Container N and ¹₁₁ of the chilli powder in Container M was 560 g. If ⁴₁₁ of the chilli powder in Container M was poured out, the total mass of the chilli powder in both containers became 2.72 kg. How much chilli powder was in

1. Container M in grams?
2. Container N in grams?

(a)
Let the mass of the chilli powder in Container N be N.
Let the mass of the chilli powder in Container M be M.

¹₄ N + ¹₁₁ M = 560 --- (1)

Fraction of the chilli powder left in Container M after ⁴₁₁ of it was poured out
= 1 - ⁴₁₁
= ⁷₁₁

1 kg = 1000 g
2.72 kg = 2720 g

1 N + ⁷₁₁ M = 2720
1 N = 2720 - ⁷₁₁ M --- (2)

Make N the same.

(1)_x4
⁴₄ N + ⁴₁₁ M = 2240
1 N + ⁴₁₁ M = 2240
1 N = 2240 - ⁴₁₁ M --- (3)

(3) = (2) 
2240 - ⁴₁₁ M = 2720 - ⁷₁₁ X
⁷₁₁ M - ⁴₁₁ M = 2720 - 2240
³₁₁ M = 480
¹₁₁ M = 480 ÷ 3 = 160

¹¹₁₁ M = 11 x 160 = 1760

1 M = 1760

Mass of Container M = 1760 g

(b)
From (1)
¹₄ N + 160 = 560
¹₄ N = 560 - 160 = 400

⁴₄ N = 4 x 400 = 1600

1 N = 1600

Mass of Container N = 1600 g

Answer(s): (a) 1760 g; (b) 1600 g