Container K and Container L were filled completely with pepper. The total mass of ¹₄ of the pepper in Container L and ¹₁₃ of the pepper in Container K was 630 g. If ³₁₃ of the pepper in Container K was poured out, the total mass of the pepper in both containers became 3.72 kg. How much pepper was in

1. Container K in grams?
2. Container L in grams?

(a)
Let the mass of the pepper in Container L be L.
Let the mass of the pepper in Container K be K.

¹₄ L + ¹₁₃ K = 630 --- (1)

Fraction of the pepper left in Container K after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.72 kg = 3720 g

1 L + ¹⁰₁₃ K = 3720
1 L = 3720 - ¹⁰₁₃ K --- (2)

Make L the same.

(1)_x4
⁴₄ L + ⁴₁₃ K = 2520
1 L + ⁴₁₃ K = 2520
1 L = 2520 - ⁴₁₃ K --- (3)

(3) = (2) 
2520 - ⁴₁₃ K = 3720 - ¹⁰₁₃ X
¹⁰₁₃ K - ⁴₁₃ K = 3720 - 2520
⁶₁₃ K = 1200
¹₁₃ K = 1200 ÷ 6 = 200

¹³₁₃ K = 13 x 200 = 2600

1 K = 2600

Mass of Container K = 2600 g

(b)
From (1)
¹₄ L + 200 = 630
¹₄ L = 630 - 200 = 430

⁴₄ L = 4 x 430 = 1720

1 L = 1720

Mass of Container L = 1720 g

Answer(s): (a) 2600 g; (b) 1720 g