Container T and Container U were filled completely with pepper. The total mass of ¹₆ of the pepper in Container U and ¹₁₃ of the pepper in Container T was 580 g. If ³₁₃ of the pepper in Container T was poured out, the total mass of the pepper in both containers became 4.16 kg. How much pepper was in

1. Container T in grams?
2. Container U in grams?

(a)
Let the mass of the pepper in Container U be U.
Let the mass of the pepper in Container T be T.

¹₆ U + ¹₁₃ T = 580 --- (1)

Fraction of the pepper left in Container T after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
4.16 kg = 4160 g

1 U + ¹⁰₁₃ T = 4160
1 U = 4160 - ¹⁰₁₃ T --- (2)

Make U the same.

(1)_x6
⁶₆ U + ⁶₁₃ T = 3480
1 U + ⁶₁₃ T = 3480
1 U = 3480 - ⁶₁₃ T --- (3)

(3) = (2) 
3480 - ⁶₁₃ T = 4160 - ¹⁰₁₃ X
¹⁰₁₃ T - ⁶₁₃ T = 4160 - 3480
⁴₁₃ T = 680
¹₁₃ T = 680 ÷ 4 = 170

¹³₁₃ T = 13 x 170 = 2210

1 T = 2210

Mass of Container T = 2210 g

(b)
From (1)
¹₆ U + 170 = 580
¹₆ U = 580 - 170 = 410

⁶₆ U = 6 x 410 = 2460

1 U = 2460

Mass of Container U = 2460 g

Answer(s): (a) 2210 g; (b) 2460 g