Container Y and Container Z were filled completely with sugar. The total mass of ¹₇ of the sugar in Container Z and ¹₁₃ of the sugar in Container Y was 480 g. If ³₁₃ of the sugar in Container Y was poured out, the total mass of the sugar in both containers became 3.75 kg. How much sugar was in

1. Container Y in grams?
2. Container Z in grams?

(a)
Let the mass of the sugar in Container Z be Z.
Let the mass of the sugar in Container Y be Y.

¹₇ Z + ¹₁₃ Y = 480 --- (1)

Fraction of the sugar left in Container Y after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
3.75 kg = 3750 g

1 Z + ¹⁰₁₃ Y = 3750
1 Z = 3750 - ¹⁰₁₃ Y --- (2)

Make Z the same.

(1)_x7
⁷₇ Z + ⁷₁₃ Y = 3360
1 Z + ⁷₁₃ Y = 3360
1 Z = 3360 - ⁷₁₃ Y --- (3)

(3) = (2) 
3360 - ⁷₁₃ Y = 3750 - ¹⁰₁₃ X
¹⁰₁₃ Y - ⁷₁₃ Y = 3750 - 3360
³₁₃ Y = 390
¹₁₃ Y = 390 ÷ 3 = 130

¹³₁₃ Y = 13 x 130 = 1690

1 Y = 1690

Mass of Container Y = 1690 g

(b)
From (1)
¹₇ Z + 130 = 480
¹₇ Z = 480 - 130 = 350

⁷₇ Z = 7 x 350 = 2450

1 Z = 2450

Mass of Container Z = 2450 g

Answer(s): (a) 1690 g; (b) 2450 g