Container S and Container T were filled completely with bread flour. The total mass of ¹₄ of the bread flour in Container T and ¹₁₃ of the bread flour in Container S was 560 g. If ³₁₃ of the bread flour in Container S was poured out, the total mass of the bread flour in both containers became 2.96 kg. How much bread flour was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the bread flour in Container T be T.
Let the mass of the bread flour in Container S be S.

¹₄ T + ¹₁₃ S = 560 --- (1)

Fraction of the bread flour left in Container S after ³₁₃ of it was poured out
= 1 - ³₁₃
= ¹⁰₁₃

1 kg = 1000 g
2.96 kg = 2960 g

1 T + ¹⁰₁₃ S = 2960
1 T = 2960 - ¹⁰₁₃ S --- (2)

Make T the same.

(1)_x4
⁴₄ T + ⁴₁₃ S = 2240
1 T + ⁴₁₃ S = 2240
1 T = 2240 - ⁴₁₃ S --- (3)

(3) = (2) 
2240 - ⁴₁₃ S = 2960 - ¹⁰₁₃ X
¹⁰₁₃ S - ⁴₁₃ S = 2960 - 2240
⁶₁₃ S = 720
¹₁₃ S = 720 ÷ 6 = 120

¹³₁₃ S = 13 x 120 = 1560

1 S = 1560

Mass of Container S = 1560 g

(b)
From (1)
¹₄ T + 120 = 560
¹₄ T = 560 - 120 = 440

⁴₄ T = 4 x 440 = 1760

1 T = 1760

Mass of Container T = 1760 g

Answer(s): (a) 1560 g; (b) 1760 g