Container V and Container W were filled completely with pepper. The total mass of ¹₆ of the pepper in Container W and ¹₁₁ of the pepper in Container V was 480 g. If ³₁₁ of the pepper in Container V was poured out, the total mass of the pepper in both containers became 3.12 kg. How much pepper was in

1. Container V in grams?
2. Container W in grams?

(a)
Let the mass of the pepper in Container W be W.
Let the mass of the pepper in Container V be V.

¹₆ W + ¹₁₁ V = 480 --- (1)

Fraction of the pepper left in Container V after ³₁₁ of it was poured out
= 1 - ³₁₁
= ⁸₁₁

1 kg = 1000 g
3.12 kg = 3120 g

1 W + ⁸₁₁ V = 3120
1 W = 3120 - ⁸₁₁ V --- (2)

Make W the same.

(1)_x6
⁶₆ W + ⁶₁₁ V = 2880
1 W + ⁶₁₁ V = 2880
1 W = 2880 - ⁶₁₁ V --- (3)

(3) = (2) 
2880 - ⁶₁₁ V = 3120 - ⁸₁₁ X
⁸₁₁ V - ⁶₁₁ V = 3120 - 2880
²₁₁ V = 240
¹₁₁ V = 240 ÷ 2 = 120

¹¹₁₁ V = 11 x 120 = 1320

1 V = 1320

Mass of Container V = 1320 g

(b)
From (1)
¹₆ W + 120 = 480
¹₆ W = 480 - 120 = 360

⁶₆ W = 6 x 360 = 2160

1 W = 2160

Mass of Container W = 2160 g

Answer(s): (a) 1320 g; (b) 2160 g