Container H and Container J were filled completely with pepper. The total mass of ¹₄ of the pepper in Container J and ¹₁₁ of the pepper in Container H was 600 g. If ⁴₁₁ of the pepper in Container H was poured out, the total mass of the pepper in both containers became 2.91 kg. How much pepper was in

1. Container H in grams?
2. Container J in grams?

(a)
Let the mass of the pepper in Container J be J.
Let the mass of the pepper in Container H be H.

¹₄ J + ¹₁₁ H = 600 --- (1)

Fraction of the pepper left in Container H after ⁴₁₁ of it was poured out
= 1 - ⁴₁₁
= ⁷₁₁

1 kg = 1000 g
2.91 kg = 2910 g

1 J + ⁷₁₁ H = 2910
1 J = 2910 - ⁷₁₁ H --- (2)

Make J the same.

(1)_x4
⁴₄ J + ⁴₁₁ H = 2400
1 J + ⁴₁₁ H = 2400
1 J = 2400 - ⁴₁₁ H --- (3)

(3) = (2) 
2400 - ⁴₁₁ H = 2910 - ⁷₁₁ X
⁷₁₁ H - ⁴₁₁ H = 2910 - 2400
³₁₁ H = 510
¹₁₁ H = 510 ÷ 3 = 170

¹¹₁₁ H = 11 x 170 = 1870

1 H = 1870

Mass of Container H = 1870 g

(b)
From (1)
¹₄ J + 170 = 600
¹₄ J = 600 - 170 = 430

⁴₄ J = 4 x 430 = 1720

1 J = 1720

Mass of Container J = 1720 g

Answer(s): (a) 1870 g; (b) 1720 g