Container S and Container T were filled completely with chicken powder. The total mass of ¹₃ of the chicken powder in Container T and ¹₁₃ of the chicken powder in Container S was 420 g. If ²₁₃ of the chicken powder in Container S was poured out, the total mass of the chicken powder in both containers became 2.06 kg. How much chicken powder was in

1. Container S in grams?
2. Container T in grams?

(a)
Let the mass of the chicken powder in Container T be T.
Let the mass of the chicken powder in Container S be S.

¹₃ T + ¹₁₃ S = 420 --- (1)

Fraction of the chicken powder left in Container S after ²₁₃ of it was poured out
= 1 - ²₁₃
= ¹¹₁₃

1 kg = 1000 g
2.06 kg = 2060 g

1 T + ¹¹₁₃ S = 2060
1 T = 2060 - ¹¹₁₃ S --- (2)

Make T the same.

(1)_x3
³₃ T + ³₁₃ S = 1260
1 T + ³₁₃ S = 1260
1 T = 1260 - ³₁₃ S --- (3)

(3) = (2) 
1260 - ³₁₃ S = 2060 - ¹¹₁₃ X
¹¹₁₃ S - ³₁₃ S = 2060 - 1260
⁸₁₃ S = 800
¹₁₃ S = 800 ÷ 8 = 100

¹³₁₃ S = 13 x 100 = 1300

1 S = 1300

Mass of Container S = 1300 g

(b)
From (1)
¹₃ T + 100 = 420
¹₃ T = 420 - 100 = 320

³₃ T = 3 x 320 = 960

1 T = 960

Mass of Container T = 960 g

Answer(s): (a) 1300 g; (b) 960 g