Jade packed some chocolate bars for a party. She packed
23 of the chocolate bars into 10 blue bags and the rest into 30 violet bags. There were 80 chocolate bars altogether in 1 blue and 2 violet bags. How many chocolate bars did Jade have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
10 |
30 |
| Number of chocolate bars |
2 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
2 u = 10 B
1 u = 5 B --- (1)
1 u = 30 V --- (2)
(1) = (2)
5 B = 30 V
1 B = 30 ÷ 5 = 6 V
1 B + 2 V = 80 --- (3)
Substitute 1 B = 6 V into (3).
6 V + 2 V = 80
8 V = 80
1 V = 80 ÷ 8 = 10
From (2)
1 u = 30 V
1 u = 30 x 10 = 300
Number of chocolate bars that Jade had at first
= 2 u + 1 u
= 3 u
= 3 x 300
= 900
Answer(s): 900
