Opal packed some candies for a party. She packed
56 of the candies into 20 blue bags and the rest into 28 violet bags. There were 20 candies altogether in 1 blue and 3 violet bags. How many candies did Opal have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
20 |
28 |
| Number of candies |
5 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
5 u = 20 B
1 u = 4 B --- (1)
1 u = 28 V --- (2)
(1) = (2)
4 B = 28 V
1 B = 28 ÷ 4 = 7 V
1 B + 3 V = 20 --- (3)
Substitute 1 B = 7 V into (3).
7 V + 3 V = 20
10 V = 20
1 V = 20 ÷ 10 = 2
From (2)
1 u = 28 V
1 u = 28 x 2 = 56
Number of candies that Opal had at first
= 5 u + 1 u
= 6 u
= 6 x 56
= 336
Answer(s): 336
