Zoe packed some sweets for a party. She packed
67 of the sweets into 36 blue bags and the rest into 24 violet bags. There were 35 sweets altogether in 1 blue and 3 violet bags. How many sweets did Zoe have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
36 |
24 |
| Number of sweets |
6 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
6 u = 36 B
1 u = 6 B --- (1)
1 u = 24 V --- (2)
(1) = (2)
6 B = 24 V
1 B = 24 ÷ 6 = 4 V
1 B + 3 V = 35 --- (3)
Substitute 1 B = 4 V into (3).
4 V + 3 V = 35
7 V = 35
1 V = 35 ÷ 7 = 5
From (2)
1 u = 24 V
1 u = 24 x 5 = 120
Number of sweets that Zoe had at first
= 6 u + 1 u
= 7 u
= 7 x 120
= 840
Answer(s): 840
