Eva packed some sweets for a party. She packed
56 of the sweets into 35 blue bags and the rest into 14 violet bags. There were 40 sweets altogether in 1 blue and 3 violet bags. How many sweets did Eva have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
35 |
14 |
| Number of sweets |
5 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
5 u = 35 B
1 u = 7 B --- (1)
1 u = 14 V --- (2)
(1) = (2)
7 B = 14 V
1 B = 14 ÷ 7 = 2 V
1 B + 3 V = 40 --- (3)
Substitute 1 B = 2 V into (3).
2 V + 3 V = 40
5 V = 40
1 V = 40 ÷ 5 = 8
From (2)
1 u = 14 V
1 u = 14 x 8 = 112
Number of sweets that Eva had at first
= 5 u + 1 u
= 6 u
= 6 x 112
= 672
Answer(s): 672
