Kathy packed some chocolate bars for a party. She packed
34 of the chocolate bars into 18 blue bags and the rest into 18 violet bags. There were 40 chocolate bars altogether in 1 blue and 2 violet bags. How many chocolate bars did Kathy have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
18 |
18 |
| Number of chocolate bars |
3 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
3 u = 18 B
1 u = 6 B --- (1)
1 u = 18 V --- (2)
(1) = (2)
6 B = 18 V
1 B = 18 ÷ 6 = 3 V
1 B + 2 V = 40 --- (3)
Substitute 1 B = 3 V into (3).
3 V + 2 V = 40
5 V = 40
1 V = 40 ÷ 5 = 8
From (2)
1 u = 18 V
1 u = 18 x 8 = 144
Number of chocolate bars that Kathy had at first
= 3 u + 1 u
= 4 u
= 4 x 144
= 576
Answer(s): 576
