Diana packed some chocolate bars for a party. She packed
56 of the chocolate bars into 25 blue bags and the rest into 30 violet bags. There were 90 chocolate bars altogether in 1 blue and 3 violet bags. How many chocolate bars did Diana have at first?
| |
Blue bags |
Violet bags |
| Number of bags |
25 |
30 |
| Number of chocolate bars |
5 u |
1 u |
Let 1 B be 1 blue bag.
Let 1 V be 1 violet bag.
5 u = 25 B
1 u = 5 B --- (1)
1 u = 30 V --- (2)
(1) = (2)
5 B = 30 V
1 B = 30 ÷ 5 = 6 V
1 B + 3 V = 90 --- (3)
Substitute 1 B = 6 V into (3).
6 V + 3 V = 90
9 V = 90
1 V = 90 ÷ 9 = 10
From (2)
1 u = 30 V
1 u = 30 x 10 = 300
Number of chocolate bars that Diana had at first
= 5 u + 1 u
= 6 u
= 6 x 300
= 1800
Answer(s): 1800
