The stadium tickets are priced at $9 and $7.  The number of $9-dollar tickets available is  1¹₂ that of the number of $7-dollar tickets. 3 out of 5 of the $9-dollar tickets and all the $7-dollar tickets were sold. The ticket sales amounted to $453. How much more would have been collected if all the tickets were sold?

	$9	$7
Comparing $9 and $7 tickets at first	3x5 = 15 u	2x5 = 10 u
Before	5x3 = 15 u
Change	- 3x3 = - 9 u	- 10 u
After	2x3 = 6 u	0 u

The number of 9 tickets at first is repeated.  Make the number of 9 tickets the same.  LCM of 5 and 3 is 15.

1¹₂ = ³₂

Number of $9 tickets : $7 tickets = 3 : 2

	$9	$7	Total
Number	9 u	10 u
Value	$9	$7
Total value	81 u	70 u	$453

Total amount collected from the sale of the sold tickets
= 81 u + 70 u
= 151 u

1 u = 453 ÷ 151 = 3

Number of $9-tickets left unsold
= 6 u 
= 6 x 3
= 18

More amount to be collected if all the tickets were sold
= 18 x 9
= $162

Answer(s): $162