The park tickets are priced at $21 and $17. The number of $21-dollar tickets available is 1
15 that of the number of $17-dollar tickets. 3 out of 5 of the $21-dollar tickets and all the $17-dollar tickets were sold. The ticket sales amounted to $7227. How much more would have been collected if all the tickets were sold?
|
$21 |
$17 |
Comparing $21 and $17 tickets at first |
6x5 = 30 u |
5x5 = 25 u |
Before |
5x6 = 30 u |
|
Change |
- 3x6 = - 18 u |
- 25 u |
After |
2x6 = 12 u |
0 u |
The number of 21 tickets at first is repeated. Make the number of 21 tickets the same. LCM of 5 and 6 is 30.
1
15 =
65 Number of $21 tickets : $17 tickets = 6 : 5
|
$21 |
$17 |
Total |
Number |
18 u |
25 u |
|
Value |
$21 |
$17 |
|
Total value |
378 u |
425 u |
$7227 |
Total amount collected from the sale of the sold tickets
= 378 u + 425 u
= 803 u
1 u = 7227 ÷ 803 = 9
Number of $21-tickets left unsold
= 12 u
= 12 x 9
= 108
More amount to be collected if all the tickets were sold
= 108 x 21
= $2268
Answer(s): $2268