The tourist attraction tickets are priced at $22 and $15.  The number of $22-dollar tickets available is  1¹₂ that of the number of $15-dollar tickets. 2 out of 5 of the $22-dollar tickets and all the $15-dollar tickets were sold. The ticket sales amounted to $2820. How much more would have been collected if all the tickets were sold?

	$22	$15
Comparing $22 and $15 tickets at first	3x5 = 15 u	2x5 = 10 u
Before	5x3 = 15 u
Change	- 2x3 = - 6 u	- 10 u
After	3x3 = 9 u	0 u

The number of 22 tickets at first is repeated.  Make the number of 22 tickets the same.  LCM of 5 and 3 is 15.

1¹₂ = ³₂

Number of $22 tickets : $15 tickets = 3 : 2

	$22	$15	Total
Number	6 u	10 u
Value	$22	$15
Total value	132 u	150 u	$2820

Total amount collected from the sale of the sold tickets
= 132 u + 150 u
= 282 u

1 u = 2820 ÷ 282 = 10

Number of $22-tickets left unsold
= 9 u 
= 9 x 10
= 90

More amount to be collected if all the tickets were sold
= 90 x 22
= $1980

Answer(s): $1980