The tourist attraction tickets are priced at $18 and $10. The number of $18-dollar tickets available is 1
12 that of the number of $10-dollar tickets. 3 out of 4 of the $18-dollar tickets and all the $10-dollar tickets were sold. The ticket sales amounted to $484. How much more would have been collected if all the tickets were sold?
|
$18 |
$10 |
Comparing $18 and $10 tickets at first |
3x4 = 12 u |
2x4 = 8 u |
Before |
4x3 = 12 u |
|
Change |
- 3x3 = - 9 u |
- 8 u |
After |
1x3 = 3 u |
0 u |
The number of 18 tickets at first is repeated. Make the number of 18 tickets the same. LCM of 4 and 3 is 12.
1
12 =
32 Number of $18 tickets : $10 tickets = 3 : 2
|
$18 |
$10 |
Total |
Number |
9 u |
8 u |
|
Value |
$18 |
$10 |
|
Total value |
162 u |
80 u |
$484 |
Total amount collected from the sale of the sold tickets
= 162 u + 80 u
= 242 u
1 u = 484 ÷ 242 = 2
Number of $18-tickets left unsold
= 3 u
= 3 x 2
= 6
More amount to be collected if all the tickets were sold
= 6 x 18
= $108
Answer(s): $108