The park tickets are priced at $21 and $14. The number of $21-dollar tickets available is 1
12 that of the number of $14-dollar tickets. 3 out of 4 of the $21-dollar tickets and all the $14-dollar tickets were sold. The ticket sales amounted to $3311. How much more would have been collected if all the tickets were sold?
|
$21 |
$14 |
Comparing $21 and $14 tickets at first |
3x4 = 12 u |
2x4 = 8 u |
Before |
4x3 = 12 u |
|
Change |
- 3x3 = - 9 u |
- 8 u |
After |
1x3 = 3 u |
0 u |
The number of 21 tickets at first is repeated. Make the number of 21 tickets the same. LCM of 4 and 3 is 12.
1
12 =
32 Number of $21 tickets : $14 tickets = 3 : 2
|
$21 |
$14 |
Total |
Number |
9 u |
8 u |
|
Value |
$21 |
$14 |
|
Total value |
189 u |
112 u |
$3311 |
Total amount collected from the sale of the sold tickets
= 189 u + 112 u
= 301 u
1 u = 3311 ÷ 301 = 11
Number of $21-tickets left unsold
= 3 u
= 3 x 11
= 33
More amount to be collected if all the tickets were sold
= 33 x 21
= $693
Answer(s): $693