The park tickets are priced at $18 and $10. The number of $18-dollar tickets available is 2
34 that of the number of $10-dollar tickets. 2 out of 5 of the $18-dollar tickets and all the $10-dollar tickets were sold. The ticket sales amounted to $3576. How much more would have been collected if all the tickets were sold?
|
$18 |
$10 |
Comparing $18 and $10 tickets at first |
11x5 = 55 u |
4x5 = 20 u |
Before |
5x11 = 55 u |
|
Change |
- 2x11 = - 22 u |
- 20 u |
After |
3x11 = 33 u |
0 u |
The number of 18 tickets at first is repeated. Make the number of 18 tickets the same. LCM of 5 and 11 is 55.
2
34 =
114 Number of $18 tickets : $10 tickets = 11 : 4
|
$18 |
$10 |
Total |
Number |
22 u |
20 u |
|
Value |
$18 |
$10 |
|
Total value |
396 u |
200 u |
$3576 |
Total amount collected from the sale of the sold tickets
= 396 u + 200 u
= 596 u
1 u = 3576 ÷ 596 = 6
Number of $18-tickets left unsold
= 33 u
= 33 x 6
= 198
More amount to be collected if all the tickets were sold
= 198 x 18
= $3564
Answer(s): $3564