The theme park tickets are priced at $26 and $20. The number of $26-dollar tickets available is 1
34 that of the number of $20-dollar tickets. 3 out of 5 of the $26-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $1892. How much more would have been collected if all the tickets were sold?
|
$26 |
$20 |
Comparing $26 and $20 tickets at first |
7x5 = 35 u |
4x5 = 20 u |
Before |
5x7 = 35 u |
|
Change |
- 3x7 = - 21 u |
- 20 u |
After |
2x7 = 14 u |
0 u |
The number of 26 tickets at first is repeated. Make the number of 26 tickets the same. LCM of 5 and 7 is 35.
1
34 =
74 Number of $26 tickets : $20 tickets = 7 : 4
|
$26 |
$20 |
Total |
Number |
21 u |
20 u |
|
Value |
$26 |
$20 |
|
Total value |
546 u |
400 u |
$1892 |
Total amount collected from the sale of the sold tickets
= 546 u + 400 u
= 946 u
1 u = 1892 ÷ 946 = 2
Number of $26-tickets left unsold
= 14 u
= 14 x 2
= 28
More amount to be collected if all the tickets were sold
= 28 x 26
= $728
Answer(s): $728