The museum tickets are priced at $16 and $8. The number of $16-dollar tickets available is 2
12 that of the number of $8-dollar tickets. 2 out of 3 of the $16-dollar tickets and all the $8-dollar tickets were sold. The ticket sales amounted to $1872. How much more would have been collected if all the tickets were sold?
|
$16 |
$8 |
Comparing $16 and $8 tickets at first |
5x3 = 15 u |
2x3 = 6 u |
Before |
3x5 = 15 u |
|
Change |
- 2x5 = - 10 u |
- 6 u |
After |
1x5 = 5 u |
0 u |
The number of 16 tickets at first is repeated. Make the number of 16 tickets the same. LCM of 3 and 5 is 15.
2
12 =
52 Number of $16 tickets : $8 tickets = 5 : 2
|
$16 |
$8 |
Total |
Number |
10 u |
6 u |
|
Value |
$16 |
$8 |
|
Total value |
160 u |
48 u |
$1872 |
Total amount collected from the sale of the sold tickets
= 160 u + 48 u
= 208 u
1 u = 1872 ÷ 208 = 9
Number of $16-tickets left unsold
= 5 u
= 5 x 9
= 45
More amount to be collected if all the tickets were sold
= 45 x 16
= $720
Answer(s): $720