The park tickets are priced at $8 and $5.  The number of $8-dollar tickets available is  1³₅ that of the number of $5-dollar tickets. 2 out of 5 of the $8-dollar tickets and all the $5-dollar tickets were sold. The ticket sales amounted to $506. How much more would have been collected if all the tickets were sold?

	$8	$5
Comparing $8 and $5 tickets at first	8x5 = 40 u	5x5 = 25 u
Before	5x8 = 40 u
Change	- 2x8 = - 16 u	- 25 u
After	3x8 = 24 u	0 u

The number of 8 tickets at first is repeated.  Make the number of 8 tickets the same.  LCM of 5 and 8 is 40.

1³₅ = ⁸₅

Number of $8 tickets : $5 tickets = 8 : 5

	$8	$5	Total
Number	16 u	25 u
Value	$8	$5
Total value	128 u	125 u	$506

Total amount collected from the sale of the sold tickets
= 128 u + 125 u
= 253 u

1 u = 506 ÷ 253 = 2

Number of $8-tickets left unsold
= 24 u 
= 24 x 2
= 48

More amount to be collected if all the tickets were sold
= 48 x 8
= $384

Answer(s): $384