The safari park tickets are priced at $29 and $20.  The number of $29-dollar tickets available is  2¹₂ that of the number of $20-dollar tickets. 2 out of 3 of the $29-dollar tickets and all the $20-dollar tickets were sold. The ticket sales amounted to $4510. How much more would have been collected if all the tickets were sold?

	$29	$20
Comparing $29 and $20 tickets at first	5x3 = 15 u	2x3 = 6 u
Before	3x5 = 15 u
Change	- 2x5 = - 10 u	- 6 u
After	1x5 = 5 u	0 u

The number of 29 tickets at first is repeated.  Make the number of 29 tickets the same.  LCM of 3 and 5 is 15.

2¹₂ = ⁵₂

Number of $29 tickets : $20 tickets = 5 : 2

	$29	$20	Total
Number	10 u	6 u
Value	$29	$20
Total value	290 u	120 u	$4510

Total amount collected from the sale of the sold tickets
= 290 u + 120 u
= 410 u

1 u = 4510 ÷ 410 = 11

Number of $29-tickets left unsold
= 5 u 
= 5 x 11
= 55

More amount to be collected if all the tickets were sold
= 55 x 29
= $1595

Answer(s): $1595