The stadium tickets are priced at $29 and $19. The number of $29-dollar tickets available is 1
15 that of the number of $19-dollar tickets. 3 out of 5 of the $29-dollar tickets and all the $19-dollar tickets were sold. The ticket sales amounted to $5982. How much more would have been collected if all the tickets were sold?
|
$29 |
$19 |
Comparing $29 and $19 tickets at first |
6x5 = 30 u |
5x5 = 25 u |
Before |
5x6 = 30 u |
|
Change |
- 3x6 = - 18 u |
- 25 u |
After |
2x6 = 12 u |
0 u |
The number of 29 tickets at first is repeated. Make the number of 29 tickets the same. LCM of 5 and 6 is 30.
1
15 =
65 Number of $29 tickets : $19 tickets = 6 : 5
|
$29 |
$19 |
Total |
Number |
18 u |
25 u |
|
Value |
$29 |
$19 |
|
Total value |
522 u |
475 u |
$5982 |
Total amount collected from the sale of the sold tickets
= 522 u + 475 u
= 997 u
1 u = 5982 ÷ 997 = 6
Number of $29-tickets left unsold
= 12 u
= 12 x 6
= 72
More amount to be collected if all the tickets were sold
= 72 x 29
= $2088
Answer(s): $2088